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Start your free trialMichael Nanni
7,358 PointsChallenge: Does the "grade" argument need a defined value? Where do I need to use "self" in feedback method?
Instructions: "Alright, I need you make a new method named feedback. It should take an argument named grade. Methods take arguments just like functions do. You'll still need self in there, though.
If grade is above 50, return the result of the praise method. If it's 50 or below, return the reassurance method's result."
class Student:
name = "Your Name"
def praise(self):
return "You inspire me, {}".format(self.name)
def reassurance(self):
return "Chin up, {}. You'll get it next time!".format(self.name)
def feedback(self, grade)
if grade > 50:
return praise(self)
else grade <== 50
return reassurance(self)
1 Answer
Steven Parker
231,269 PointsI'm not sure what you mean by "defined value" regarding "grade" (it's a parameter, so the answer is probably "no").
But the way you use "self" is as the basis for calling the internal methods, for example:
return self.praise() # instead of "praise(self)"
And a few more hints:
- the "def" line should end with a colon
- "
<==
" is not a python operator - a plain "else" does not use a conditional expression
- the "else" should also end with a colon
Michael Nanni
7,358 PointsThank you Steven Parker! I was able to complete the challenge with your tips. However, I don't understand self here and its position in the function. How should I read self.praise() vs praise(self)? Can you explain a bit more why one works the other doesn't?
Separate question, is there a more readable way to write this function other than this?
def feedback(self, grade)
if grade > 50:
return self.praise()
else:
return self.reassurance()
Thanks again!
Steven Parker
231,269 PointsI think you nailed it. Good job!
KRIS NIKOLAISEN
54,971 PointsKRIS NIKOLAISEN
54,971 PointsYou might want to try your code in a workspace and add:
You'll get better feedback than "Bummer Try Again"