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PHP PHP Basics Unit Converter Manipulating Numbers

WWU SWAT
WWU SWAT
7,316 Points
Posted by WWU SWAT
WWU SWAT
7,316 Points

Cannot seem to get past this part

Cannot seem to get a display showing a integer and float.

index.php 
<?php

//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;

$integerOne = ($integerOne + 5);
$integerTwo = ($integerTwo - 1); 

$floatOne = 1.5;

echo = ($integerOne * $floatOne);

?>

1 Answer

Umesh Ravji
Umesh Ravji
42,386 Points
Umesh Ravji
Umesh Ravji
42,386 Points

Hi Wwu, you just aren't using echo correctly. It's not a variable that you can assign something to. Its a function you can call with either a single string parameter or multiple strings. You can read more about it here http://www.w3schools.com/php/func_string_echo.asp

<?php
echo($integerOne * $floatOne);