Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript and the DOM (Retiring) Getting a Handle on the DOM Practice Selecting Elements

Posted by Alex Stout
Alex Stout
1,995 Points

Can you not use 2 selector methods joined by .notation? Why is it always an error in every variation?

It doesn't seem to matter what code I use, I select the <nav> tag with "document.getElementsByTagName("nav")" or some other method, and then I add ".children" and it will read it. But if instead I add ".getElementsByTagName("li")" or something like that I will get an error. It doesn't seem to matter if I'm using "ul" or "li" or other methods like ".querySelectorAll()" with the "#" or "." before "ul" or "li", all of it is unreadable for some reason. And even if it did work, I have no idea how to pull out the link references in particular instead of just selecting the whole collection of <li> elements. What am I doing wrong?

js/app.js 
let navigationLinks = document.getElementsByTagName("nav").getElementById("selected");
let galleryLinks;
let footerImages;
index.html 
<!DOCTYPE html>
<html>
  <head>
    <meta charset="utf-8">
    <title>Nick Pettit | Designer</title>
    <link rel="stylesheet" href="css/normalize.css">
    <link href='http://fonts.googleapis.com/css?family=Changa+One|Open+Sans:400italic,700italic,400,700,800' rel='stylesheet' type='text/css'>
    <link rel="stylesheet" href="css/main.css">
    <link rel="stylesheet" href="css/responsive.css">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
  </head>
  <body>
    <header>
      <a href="index.html" id="logo">
        <h1>Nick Pettit</h1>
        <h2>Designer</h2>
      </a>
      <nav>
        <ul>
          <li><a href="index.html" class="selected">Portfolio</a></li>
          <li><a href="about.html">About</a></li>
          <li><a href="contact.html">Contact</a></li>
        </ul>
      </nav>
    </header>
    <div id="wrapper">
      <section>
        <ul id="gallery">
          <li>
            <a href="img/numbers-01.jpg">
              <img src="img/numbers-01.jpg" alt="">
              <p>Experimentation with color and texture.</p>
            </a>
          </li>
          <li>
            <a href="img/numbers-02.jpg">
              <img src="img/numbers-02.jpg" alt="">
              <p>Playing with blending modes in Photoshop.</p>
            </a>
          </li>
        </ul>
      </section>
      <footer>
        <a href="http://twitter.com/nickrp"><img src="img/twitter-wrap.png" alt="Twitter Logo" class="social-icon"></a>
        <a href="http://facebook.com/nickpettit"><img src="img/facebook-wrap.png" alt="Facebook Logo" class="social-icon"></a>
        <p>&copy; 2016 Nick Pettit.</p>
      </footer>
    </div>
  <script src="js/app.js"></script>
  </body>
</html>

1 Answer

Peter Vann
Peter Vann
36,427 Points

Hi Alex!

This passes all 3 tasks:

let navigationLinks = document.querySelectorAll('nav a');
let galleryLinks = document.querySelectorAll('#gallery a');
let footerImages = document.querySelectorAll('footer img');

Keep in mind that the descendent selector is when you separate two selectors with a space, such as 'nav a', which selects all the anchor elements that are the children of the nav element.

I hope that helps.

Stay safe and happy coding!