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Python Introducing Lists Build an Application Multidimensional Musical Groups

Diego Dillon
Diego Dillon
655 Points
Posted by Diego Dillon
Diego Dillon
655 Points

Can you loop through each group and output the members joined together with a ", " comma space as a separator

musical_groups = [ ["Ad Rock", "MCA", "Mike D."], ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"], ["Salt", "Peppa", "Spinderella"], ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"], ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"], ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"], ["Run", "DMC", "Jam Master Jay"],

groups.py 
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
# Your code here
Craig Dennis
Craig Dennis
Treehouse Teacher
Craig Dennis
Craig Dennis
Treehouse Teacher

Hi Diego Dillon !

Do you have a specific question about the challenge? I'd be happy to help

Remember, this is a list of lists.

2 Answers

Peshal Parajuli
Peshal Parajuli
1,452 Points
Peshal Parajuli
Peshal Parajuli
1,452 Points 
for loop in musical_groups:
    print((", ".join(loop)))
Christian Berglönn
Christian Berglönn
3,274 Points
Christian Berglönn
Christian Berglönn
3,274 Points

Can you explain why it's written like that?

Andrew Krause
Andrew Krause
10,679 Points
Andrew Krause
Andrew Krause
10,679 Points

Here's a bit cleaner of an example, as a pair of parenthesis are not needed. I've created a comma variable so its a little easier to read:

comma = ", "
for group in musical_groups:
    print(comma.join(group))

group in musical_groups allows you to get each group. Then, all you have to do is join them together and separate each name with a comma.