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Start your free trialsteeve Francois
Courses Plus Student 572 Pointscan someone me with this.....Use Console.WriteLine to print the contents of the firstName variable to the screen.
I did the first two line but there is something wrong with the third one
string firstName;
string fisrtName = Console.ReadLine();
Console.WriteLine("firstName");
2 Answers
Steven Parker
231,210 PointsDon't put quotes around your variable name.
That makes it a literal string, but you want to use the variable which represents the name that was assigned.
Also, you can only declare a variable once, whether or not you initialize it at the same time. So you don't need the first line at all.
Terry Bowyer
2,450 PointsI tried this answer.
- It worked for me without the second object 'string'
- Careful of the spelling for the firstName variable on line two :-)