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![Devin Cushard](https://uploads.teamtreehouse.com/production/profile-photos/11691830/micro_20220618_120749.jpg)
Devin Cushard
2,236 PointsCan anybody explain to me why my if statement doesn't work? I thought you could use an isNaN statement like this?
// Collect input from a user
const num=parseFloat(prompt("Please provide a number"));
if(isNaN === num){
console.log(This is not a number
);
} else{
// Convert the input to a number
// Use Math.random() and the user's number to generate a random number const random = Math.floor(Math.random()*num)+1;
// Create a message displaying the random number
console.log(${random} is a number between 1 and ${num}
);
}
1 Answer
![Steven Parker](https://uploads.teamtreehouse.com/production/profile-photos/969492/micro_tool_chess_set_2.jpg)
Steven Parker
230,688 PointsIt looks like you're using "isNaN" as a value, but it's a function. The proper syntax to test a variable named "num" to see if it is not a number would be: isNaN(num)
Devin Cushard
2,236 PointsDevin Cushard
2,236 PointsThank you, I'm so embarrassed.