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Python Python Basics (2015) Letter Game App Random Item

Vikshith Vishwanath
PLUS
Vikshith Vishwanath
Courses Plus Student 820 Points
Posted by Vikshith Vishwanath
Vikshith Vishwanath
Courses Plus Student 820 Points

Bummer! Didn't get a correct option back from 'random_item'

import random

def random_item(iterable): num = iterable[random.randint(0,len(iterable)-1))] return(num)

actually this code works and the one without the iterable in the line 4 (just like the one attached ) doesn't work. why is it doesn't work?

item.py 
# EXAMPLE
# random_item("Treehouse")
# The randomly selected number is 4.
# The return value would be "h"
import random

def random_item(iterable):
    num = random.randint(0,len(iterable)-1)
    return(num)

1 Answer

Jennifer Nordell
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STAFF
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Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! They're correct. You're not returning the correct thing. You randomly generate a number and then you're returning that number. What they want is for you to return the letter at that index.

So let's say you randomly generated a 2. It would want you to return the thing at index 2 of the iterable passed in. In this example, it would be iterable[2].

Hope this hint helps! :sparkles: