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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Posted by Raedawn Long
Raedawn Long
6,943 Points

Assistance with passing agruements while calling.

passing arguments

script.js 
function returnValue (echo) {
var echo   
 return ('echo'); 
}
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

4 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You don't need to create a new variable in this function. And you would certainly not want to create one with the same name as a parameter. This causes what is known as "shadowing" and makes the parameter inaccessible.

Also, don't enclose a variable name in quotes. Anything in quotes is treated as a string literal and not a variable.

Raedawn Long
Raedawn Long
6,943 Points
Raedawn Long
Raedawn Long
6,943 Points

yaaayyy!! figured it out! ty again!

Raedawn Long
Raedawn Long
6,943 Points
Raedawn Long
Raedawn Long
6,943 Points

Hey Steven, can you give me an example on how to start a max function with numbers its my last objective ?

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

A "max" function would take two arguments, perform a test to see which one is larger, and return the larger one.

Raedawn Long
Raedawn Long
6,943 Points
Raedawn Long
Raedawn Long
6,943 Points

I thought so, I keep getting error I put ex

function max(width, length) {

}

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

That's a good start, but now you need the body code to perform the test and returns.

Raedawn Long — We seem to have wandered off the original topic. If the original question has been answered, you can mark it solved by choosing a "best answer".

Happy coding!