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Java Java Basics Perfecting the Prototype String Equality

Posted by ibrahim issa
ibrahim issa
Courses Plus Student 354 Points

Add another if statement that checks if the firstExample is equal ignoring case to thirdExample.

how do we do this??

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample == secondExample) {
  console.printf("first is equal to second");
}
if (firstExample.equalsIgnoringCase("thirdExample")) {
  console.printf("first and third are the same ignoring case")
}

2 Answers

Jason Anello
PLUS
Jason Anello
Courses Plus Student 94,610 Points
Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Hi ibrahim,

You have a few problems.

Your second printf doesn't end with a semi-colon.

The correct method name is equalsIgnoreCase

Also, you're checking if it's equal to the string "thirdExample". You have to remove the quotes so that you're using the variable.

Alexander Davison
Alexander Davison
65,469 Points

Upvoted :wink:

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

First, equalsIgnoringCase isn't a Java method. However, there is a method called equalsIgnoreCase. Also, you shouldn't use quotes when referring to the thirdExample variable. If you have parentheses, it will actually compare fistExample to literally the "thirdExample" string itself, not the value of the thirdExample variable.

EDIT: I also noticed that you missed a semicolon ; on line 9 (where console.printf("first and third are the same ignoring case") is).

Remove the quotes around thirdExample and change equalsIgnoringCase to equalsIgnoreCase and your should be good to go :smile:

I hope this helps. ~Alex