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![Tural Rzazade](https://uploads.teamtreehouse.com/production/profile-photos/11591276/micro_Tural_Rzazade.jpg)
Tural Rzazade
3,750 PointsA solution including "lower" ( "min" in the video ) value 0.
function random (lower, upper) {
let result = Math.floor(Math.random() * (upper - lower)) + lower;
return result;
}
random()
2 Answers
![Steven Parker](https://uploads.teamtreehouse.com/production/profile-photos/969492/micro_tool_chess_set_2.jpg)
Steven Parker
230,688 PointsIf you compare this to the code shown in the video, you'll see that this formula is missing the "+ 1
" which is needed to make the random range inclusive of the higher number.
![Steven Parker](https://uploads.teamtreehouse.com/production/profile-photos/969492/micro_tool_chess_set_2.jpg)
Steven Parker
230,688 PointsDid you post the wrong sample? I don't see "min" being used in this code.
![Tural Rzazade](https://uploads.teamtreehouse.com/production/profile-photos/11591276/micro_Tural_Rzazade.jpg)
Tural Rzazade
3,750 PointsRight. It had to be lower .
Tural Rzazade
3,750 PointsTural Rzazade
3,750 PointsIn that case, it excludes the 0, doesn't it?
Steven Parker
230,688 PointsSteven Parker
230,688 PointsNo, because the
+ 1
is part of the multiplier. If the random function returns 0, no matter what you multiply it by, the value will still be 0.