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Python Python Collections (2016, retired 2019) Lists Disemvowel

Mauro Y.
Mauro Y.
6,520 Points
Posted by Mauro Y.
Mauro Y.
6,520 Points

This script in not passing the challenge, but working in my machine. Why?

Made this script to remove vowels from some word. Work perfectly on my system, but is been refused by the challenge terminal. The platform alert is not helping, just says: Bummer! Try again! Some idea?

disemvowel.py 
def disemvowel(word):
    vogal = ['a', 'i','u', 'e', 'o', 'A', 'I', 'U', 'E', 'O']
    i = 0

    while i <= len(vogal) - 1:
        j = 0
        count = len(word)
        while count >= 0 :
            try:
                word.remove(vogal[i])
            except ValueError:
                pass
            count -= 1
        i += 1


    word = ''.join(word)

    return word

1 Answer

Steven Parker
Steven Parker
231,128 Points
Steven Parker
Steven Parker
231,128 Points

This worked for you?

When I tried it, I got this:

  File "disemvowel.py", line 10, in disemvowel                                                                        
    word.remove(vogal[i])                                                                                      
AttributeError: 'str' object has no attribute 'remove'

But if I modify the program so that it does not have this error, it also passes the challenge.

Mauro Y.
Mauro Y.
6,520 Points
Mauro Y.
Mauro Y.
6,520 Points

Sorry. In fact the scrip is:

def disemvowel(word):
    print(word)            
    word = list(word)

    vogal = ['a', 'i','u', 'e', 'o', 'A', 'I', 'E', 'O', 'U']
    i = 0 

    while i <= len(vogal) - 1:
        j = 0 
        count = len(word)
        while count >= 0 : 
            try:
                word.remove(vogal[i])
            except ValueError:
                pass
            count -= 1
        i += 1


    word = ''.join(word)
    return word
Steven Parker
Steven Parker
231,128 Points
Steven Parker
Steven Parker
231,128 Points

That's the same change I made, and it passes the challenge as-is (though you don't need to print anything).