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JavaScript JavaScript Basics (Retired) Storing and Tracking Information with Variables Using String Methods

Walter Alexandros Vogiatzis
PLUS
Walter Alexandros Vogiatzis
Courses Plus Student 1,778 Points

Bummer! Did you add the '#' character between `id` and `lastName`? Can someone help what am I missing?

Bummer! Did you add the '#' character between id and lastName? What am I missing? My code is: var userName = (''id".toUpperCase() + "#" + "lastName".toUpperCase());

app.js
var id = "23188xtr";
var lastName = "Smith";

var userName = ('id'.toUpperCase()+'#'+'lastName'.toUpperCase());
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="app.js"></script>
</body>
</html>

1 Answer

Justin Black
Justin Black
24,793 Points

Pretty sure your code should read:

var userName = (id.toUpperCase()+'#'+lastName.toUpperCase());
Justin Black
Justin Black
24,793 Points

No problem Walter, happy to help. Keep in mind, for future reference that in JavaScript ( and many other languages ) single quotes ( ' or ` ) and double quotes ( " ) function identical.

Anything contained within them is treated as a literal string. So, when you had 'id'.toUpperCase() you created a string object containing the word "id", and were bringing that to be uppercase resulting in "ID". This is valid, but in this particular phase of the JavaScript tutorial, you have defined the variables id and lastName.

So to use these variables, you just type out their reference identifier: console.log(id.toUpperCase()) which would be the same as typing: console.log("23188xtr".toUpperCase()) or console.log('23188xtr'.toUpperCase())