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Kody Dibble
2,554 PointsHow to write the function Python Challenge my_dict my_list
So I can't figure out how to use this code, I made the function and then the for and if statements along with the throwaway variable...
Not sure, been asking a lot of questions lately ! Thanks!
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
my_dict = {'apples': 1, 'bananas': 2, 'peaches': 5}
my_list = ['apples', 'bananas', 'peaches']
def members(my_dict, my_list):
counts = 0
for item in my_list:
if item in my_dict.keys():
counts += 1
return counts
4 Answers
William Li
Courses Plus Student 26,868 PointsYour code is all correct, only thing is that you need to fix the indentation. White spaces and indentation are of syntactic importance in Python.
def members(my_dict, my_list):
counts = 0
for item in my_list:
if item in my_dict.keys():
counts += 1
return counts
Kody Dibble
2,554 PointsSo how does Python know what item means? Does it know what key means as well?
William Li
Courses Plus Student 26,868 Pointsitem is just a name given to the loop variable, you can give it any name you want, you don't have to always name it item.
This blog post https://blog.udemy.com/python-for-loop/ does a great job at explaining Python's for loop.
Kody Dibble
2,554 PointsThe code still didn't work... Not sure whats up.
William Li
Courses Plus Student 26,868 Points
Kody Dibble
2,554 PointsHmmm how does it know where to take the list? Or does the example think it already has it.